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114255550234853 is a prime number
BaseRepresentation
bin11001111110101000110001…
…011111000100000011100101
3112222112201112202002111001022
4121332220301133010003211
5104433430331330003403
61043000135234140525
733031456021630316
oct3176506137040345
9488481482074038
10114255550234853
1133450563520665
12109935a8721745
134b9a337caa9c1
14202ddd8c6460d
15d320b08cad38
hex67ea317c40e5

114255550234853 has 2 divisors, whose sum is σ = 114255550234854. Its totient is φ = 114255550234852.

The previous prime is 114255550234811. The next prime is 114255550234901. The reversal of 114255550234853 is 358432055552411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109260651539524 + 4994898695329 = 10452782^2 + 2234927^2 .

It is a cyclic number.

It is not a de Polignac number, because 114255550234853 - 220 = 114255549186277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114255550234795 and 114255550234804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114255550237853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127775117426 + 57127775117427.

It is an arithmetic number, because the mean of its divisors is an integer number (57127775117427).

Almost surely, 2114255550234853 is an apocalyptic number.

It is an amenable number.

114255550234853 is a deficient number, since it is larger than the sum of its proper divisors (1).

114255550234853 is an equidigital number, since it uses as much as digits as its factorization.

114255550234853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400000, while the sum is 53.

The spelling of 114255550234853 in words is "one hundred fourteen trillion, two hundred fifty-five billion, five hundred fifty million, two hundred thirty-four thousand, eight hundred fifty-three".