Base | Representation |
---|---|
bin | 110101001101001111… |
… | …0001000111111110101 |
3 | 101220221000202002210021 |
4 | 1222122132020333311 |
5 | 3333001222222013 |
6 | 124253552125141 |
7 | 11153326166116 |
oct | 1523236107765 |
9 | 356830662707 |
10 | 114260742133 |
11 | 445042347aa |
12 | 1a1898367b1 |
13 | aa0c1525b5 |
14 | 575d00c20d |
15 | 2e8b1c4a8d |
hex | 1a9a788ff5 |
114260742133 has 4 divisors (see below), whose sum is σ = 114695193888. Its totient is φ = 113826290380.
The previous prime is 114260742131. The next prime is 114260742173. The reversal of 114260742133 is 331247062411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331247062411 = 269 ⋅1231401719.
It is a cyclic number.
It is not a de Polignac number, because 114260742133 - 21 = 114260742131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114260742131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217225483 + ... + 217226008.
It is an arithmetic number, because the mean of its divisors is an integer number (28673798472).
Almost surely, 2114260742133 is an apocalyptic number.
It is an amenable number.
114260742133 is a deficient number, since it is larger than the sum of its proper divisors (434451755).
114260742133 is an equidigital number, since it uses as much as digits as its factorization.
114260742133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 434451754.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 114260742133 in words is "one hundred fourteen billion, two hundred sixty million, seven hundred forty-two thousand, one hundred thirty-three".
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