Base | Representation |
---|---|
bin | 1010011001001001011011… |
… | …0011101010011111000111 |
3 | 1111110102110020211002002011 |
4 | 2212102112303222133013 |
5 | 2444210242120230002 |
6 | 40145320155155051 |
7 | 2256404155000261 |
oct | 246222663523707 |
9 | 44412406732064 |
10 | 11427143133127 |
11 | 3706251436a37 |
12 | 13467a7145a87 |
13 | 64b7622a93c7 |
14 | 2b7110598b31 |
15 | 14c3a5eac8d7 |
hex | a6496cea7c7 |
11427143133127 has 2 divisors, whose sum is σ = 11427143133128. Its totient is φ = 11427143133126.
The previous prime is 11427143133019. The next prime is 11427143133163. The reversal of 11427143133127 is 72133134172411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11427143133127 - 231 = 11424995649479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11427143133127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11427143233127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5713571566563 + 5713571566564.
It is an arithmetic number, because the mean of its divisors is an integer number (5713571566564).
Almost surely, 211427143133127 is an apocalyptic number.
11427143133127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11427143133127 is an equidigital number, since it uses as much as digits as its factorization.
11427143133127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 84672, while the sum is 40.
The spelling of 11427143133127 in words is "eleven trillion, four hundred twenty-seven billion, one hundred forty-three million, one hundred thirty-three thousand, one hundred twenty-seven".
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