Base | Representation |
---|---|
bin | 10101010010100100… |
… | …01010000101101101 |
3 | 1002111120122101201110 |
4 | 22221102022011231 |
5 | 141402042402023 |
6 | 5130105302233 |
7 | 553150525323 |
oct | 125122120555 |
9 | 32446571643 |
10 | 11430044013 |
11 | 4935a64273 |
12 | 226ba94979 |
13 | 1102057c6b |
14 | 7a6055d13 |
15 | 46d6d9a93 |
hex | 2a948a16d |
11430044013 has 4 divisors (see below), whose sum is σ = 15240058688. Its totient is φ = 7620029340.
The previous prime is 11430043991. The next prime is 11430044057. The reversal of 11430044013 is 31044003411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11430044013 - 26 = 11430043949 is a prime.
It is a super-2 number, since 2×114300440132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11430044063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905007333 + ... + 1905007338.
It is an arithmetic number, because the mean of its divisors is an integer number (3810014672).
Almost surely, 211430044013 is an apocalyptic number.
It is an amenable number.
11430044013 is a deficient number, since it is larger than the sum of its proper divisors (3810014675).
11430044013 is an equidigital number, since it uses as much as digits as its factorization.
11430044013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3810014674.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 11430044013 its reverse (31044003411), we get a palindrome (42474047424).
The spelling of 11430044013 in words is "eleven billion, four hundred thirty million, forty-four thousand, thirteen".
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