114301130331235 has 4 divisors (see below), whose sum is σ = 137161356397488. Its totient is φ = 91440904264984.

The previous prime is 114301130331151. The next prime is 114301130331301. The reversal of 114301130331235 is 532133031103411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114301130331235 - 2⁷ = 114301130331107 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114301130331197 and 114301130331206.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11430113033119 + ... + 11430113033128.

It is an arithmetic number, because the mean of its divisors is an integer number (34290339099372).

Almost surely, 2^{114301130331235} is an apocalyptic number.

114301130331235 is a deficient number, since it is larger than the sum of its proper divisors (22860226066253).

114301130331235 is an equidigital number, since it uses as much as digits as its factorization.

114301130331235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22860226066252.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 114301130331235 its reverse (532133031103411), we get a palindrome (646434161434646).

The spelling of 114301130331235 in words is "one hundred fourteen trillion, three hundred one billion, one hundred thirty million, three hundred thirty-one thousand, two hundred thirty-five".