Base | Representation |
---|---|
bin | 110101001110011101… |
… | …0101000010111111101 |
3 | 101221000212221021202001 |
4 | 1222130322220113331 |
5 | 3333042222440432 |
6 | 124302015302301 |
7 | 11154334654501 |
oct | 1523472502775 |
9 | 357025837661 |
10 | 114301765117 |
11 | 445254039a1 |
12 | 1a19b51a991 |
13 | aa177b6957 |
14 | 576464a301 |
15 | 2e8eac99e7 |
hex | 1a9cea85fd |
114301765117 has 2 divisors, whose sum is σ = 114301765118. Its totient is φ = 114301765116.
The previous prime is 114301765051. The next prime is 114301765141. The reversal of 114301765117 is 711567103411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113495545881 + 806219236 = 336891^2 + 28394^2 .
It is an emirp because it is prime and its reverse (711567103411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114301765117 - 219 = 114301240829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114301765147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150882558 + 57150882559.
It is an arithmetic number, because the mean of its divisors is an integer number (57150882559).
Almost surely, 2114301765117 is an apocalyptic number.
It is an amenable number.
114301765117 is a deficient number, since it is larger than the sum of its proper divisors (1).
114301765117 is an equidigital number, since it uses as much as digits as its factorization.
114301765117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17640, while the sum is 37.
Adding to 114301765117 its reverse (711567103411), we get a palindrome (825868868528).
The spelling of 114301765117 in words is "one hundred fourteen billion, three hundred one million, seven hundred sixty-five thousand, one hundred seventeen".
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