Base | Representation |
---|---|
bin | 10101010010101101… |
… | …11101000001011101 |
3 | 1002111200000021021102 |
4 | 22221112331001131 |
5 | 141402403114323 |
6 | 5130152242445 |
7 | 553164312533 |
oct | 125126750135 |
9 | 32450007242 |
10 | 11431301213 |
11 | 4936742882 |
12 | 22703a0425 |
13 | 11023a8277 |
14 | 7a62a2153 |
15 | 46d887328 |
hex | 2a95bd05d |
11431301213 has 4 divisors (see below), whose sum is σ = 11485478208. Its totient is φ = 11377124220.
The previous prime is 11431301209. The next prime is 11431301239. The reversal of 11431301213 is 31210313411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31210313411 = 281 ⋅111068731.
It is not a de Polignac number, because 11431301213 - 22 = 11431301209 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11431301513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27088181 + ... + 27088602.
It is an arithmetic number, because the mean of its divisors is an integer number (2871369552).
Almost surely, 211431301213 is an apocalyptic number.
It is an amenable number.
11431301213 is a deficient number, since it is larger than the sum of its proper divisors (54176995).
11431301213 is an equidigital number, since it uses as much as digits as its factorization.
11431301213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54176994.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11431301213 its reverse (31210313411), we get a palindrome (42641614624).
The spelling of 11431301213 in words is "eleven billion, four hundred thirty-one million, three hundred one thousand, two hundred thirteen".
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