1143133223441 has 4 divisors (see below), whose sum is σ = 1247054425584. Its totient is φ = 1039212021300.

The previous prime is 1143133223417. The next prime is 1143133223471. The reversal of 1143133223441 is 1443223313411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1143133223441 is a prime.

It is a super-2 number, since 2×1143133223441² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1143133223398 and 1143133223407.

It is not an unprimeable number, because it can be changed into a prime (1143133223471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51960601055 + ... + 51960601076.

It is an arithmetic number, because the mean of its divisors is an integer number (311763606396).

Almost surely, 2^{1143133223441} is an apocalyptic number.

1143133223441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1143133223441 is a deficient number, since it is larger than the sum of its proper divisors (103921202143).

1143133223441 is a wasteful number, since it uses less digits than its factorization.

1143133223441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103921202142.

The product of its digits is 20736, while the sum is 32.

Adding to 1143133223441 its reverse (1443223313411), we get a palindrome (2586356536852).

The spelling of 1143133223441 in words is "one trillion, one hundred forty-three billion, one hundred thirty-three million, two hundred twenty-three thousand, four hundred forty-one".