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11431431241 is a prime number
BaseRepresentation
bin10101010010101110…
…11100110001001001
31002111200020212122021
422221113130301021
5141402421244431
65130155124441
7553165363606
oct125127346111
932450225567
1011431431241
11493682153a
122270443721
1311024224c9
147a62d76ad
1546d8b0b11
hex2a95dcc49

11431431241 has 2 divisors, whose sum is σ = 11431431242. Its totient is φ = 11431431240.

The previous prime is 11431431233. The next prime is 11431431269. The reversal of 11431431241 is 14213413411.

11431431241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7891657225 + 3539774016 = 88835^2 + 59496^2 .

It is a cyclic number.

It is not a de Polignac number, because 11431431241 - 23 = 11431431233 is a prime.

It is not a weakly prime, because it can be changed into another prime (11431431211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715715620 + 5715715621.

It is an arithmetic number, because the mean of its divisors is an integer number (5715715621).

Almost surely, 211431431241 is an apocalyptic number.

It is an amenable number.

11431431241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11431431241 is an equidigital number, since it uses as much as digits as its factorization.

11431431241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 11431431241 its reverse (14213413411), we get a palindrome (25644844652).

The spelling of 11431431241 in words is "eleven billion, four hundred thirty-one million, four hundred thirty-one thousand, two hundred forty-one".