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114314433347 is a prime number
BaseRepresentation
bin110101001110110101…
…0111101001101000011
3101221001202202220021202
41222131222331031003
53333103443331342
6124303151011415
711154550436222
oct1523552751503
9357052686252
10114314433347
1144531576804
121a1a3809b6b
13aa1a300b4a
1457661c6cb9
152e90c7d332
hex1a9dabd343

114314433347 has 2 divisors, whose sum is σ = 114314433348. Its totient is φ = 114314433346.

The previous prime is 114314433251. The next prime is 114314433349. The reversal of 114314433347 is 743334413411.

It is a strong prime.

It is an emirp because it is prime and its reverse (743334413411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114314433347 - 218 = 114314171203 is a prime.

Together with 114314433349, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114314433347.

It is not a weakly prime, because it can be changed into another prime (114314433349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157216673 + 57157216674.

It is an arithmetic number, because the mean of its divisors is an integer number (57157216674).

Almost surely, 2114314433347 is an apocalyptic number.

114314433347 is a deficient number, since it is larger than the sum of its proper divisors (1).

114314433347 is an equidigital number, since it uses as much as digits as its factorization.

114314433347 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 145152, while the sum is 38.

Adding to 114314433347 its reverse (743334413411), we get a palindrome (857648846758).

The spelling of 114314433347 in words is "one hundred fourteen billion, three hundred fourteen million, four hundred thirty-three thousand, three hundred forty-seven".