Base | Representation |
---|---|
bin | 110101001110110111… |
… | …0101111010101101011 |
3 | 101221001211122021202111 |
4 | 1222131232233111223 |
5 | 3333104222101011 |
6 | 124303224143151 |
7 | 11154562036555 |
oct | 1523556572553 |
9 | 357054567674 |
10 | 114315425131 |
11 | 44532093966 |
12 | 1a1a4007ab7 |
13 | aa1a58a3bb |
14 | 57663a44d5 |
15 | 2e90dc7121 |
hex | 1a9dbaf56b |
114315425131 has 4 divisors (see below), whose sum is σ = 115599868200. Its totient is φ = 113030982064.
The previous prime is 114315425069. The next prime is 114315425149. The reversal of 114315425131 is 131524513411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114315425131 - 225 = 114281870699 is a prime.
It is a super-2 number, since 2×1143154251312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114315425093 and 114315425102.
It is not an unprimeable number, because it can be changed into a prime (114315455131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642221401 + ... + 642221578.
It is an arithmetic number, because the mean of its divisors is an integer number (28899967050).
Almost surely, 2114315425131 is an apocalyptic number.
114315425131 is a deficient number, since it is larger than the sum of its proper divisors (1284443069).
114315425131 is an equidigital number, since it uses as much as digits as its factorization.
114315425131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1284443068.
The product of its digits is 7200, while the sum is 31.
Adding to 114315425131 its reverse (131524513411), we get a palindrome (245839938542).
The spelling of 114315425131 in words is "one hundred fourteen billion, three hundred fifteen million, four hundred twenty-five thousand, one hundred thirty-one".
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