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114315604613 = 716330800659
BaseRepresentation
bin110101001110110111…
…1011011001010000101
3101221001211222101221222
41222131233123022011
53333104243321423
6124303232050125
711154563415050
oct1523557331205
9357054871858
10114315604613
11445321a67a1
121a1a4093945
13aa1a620cc2
14576640da97
152e90e103c8
hex1a9dbdb285

114315604613 has 4 divisors (see below), whose sum is σ = 130646405280. Its totient is φ = 97984803948.

The previous prime is 114315604609. The next prime is 114315604633. The reversal of 114315604613 is 316406513411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114315604613 - 22 = 114315604609 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114315604633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8165400323 + ... + 8165400336.

It is an arithmetic number, because the mean of its divisors is an integer number (32661601320).

Almost surely, 2114315604613 is an apocalyptic number.

It is an amenable number.

114315604613 is a deficient number, since it is larger than the sum of its proper divisors (16330800667).

114315604613 is an equidigital number, since it uses as much as digits as its factorization.

114315604613 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16330800666.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 114315604613 in words is "one hundred fourteen billion, three hundred fifteen million, six hundred four thousand, six hundred thirteen".

Divisors: 1 7 16330800659 114315604613