Base | Representation |
---|---|
bin | 110101001111000110… |
… | …0000100010111001111 |
3 | 101221002101002220010001 |
4 | 1222132030010113033 |
5 | 3333113204112143 |
6 | 124304101025131 |
7 | 11155014300451 |
oct | 1523614042717 |
9 | 357071086101 |
10 | 114323113423 |
11 | 44536465222 |
12 | 1a1a66b51a7 |
13 | aa1c04c99c |
14 | 57674062d1 |
15 | 2e918e514d |
hex | 1a9e3045cf |
114323113423 has 2 divisors, whose sum is σ = 114323113424. Its totient is φ = 114323113422.
The previous prime is 114323113409. The next prime is 114323113433. The reversal of 114323113423 is 324311323411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114323113423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114323113391 and 114323113400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114323113433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57161556711 + 57161556712.
It is an arithmetic number, because the mean of its divisors is an integer number (57161556712).
Almost surely, 2114323113423 is an apocalyptic number.
114323113423 is a deficient number, since it is larger than the sum of its proper divisors (1).
114323113423 is an equidigital number, since it uses as much as digits as its factorization.
114323113423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 28.
Adding to 114323113423 its reverse (324311323411), we get a palindrome (438634436834).
The spelling of 114323113423 in words is "one hundred fourteen billion, three hundred twenty-three million, one hundred thirteen thousand, four hundred twenty-three".
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