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114325112903 = 151757119953
BaseRepresentation
bin110101001111001001…
…1101100100001000111
3101221002111212110212212
41222132103230201013
53333114212103103
6124304211534035
711155040266031
oct1523623544107
9357074773785
10114325112903
1144537600491
121a1a72ba31b
13aa1c59cb01
1457677a6c51
152e91b8c7d8
hex1a9e4ec847

114325112903 has 4 divisors (see below), whose sum is σ = 115082233008. Its totient is φ = 113567992800.

The previous prime is 114325112887. The next prime is 114325112927. The reversal of 114325112903 is 309211523411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114325112903 - 24 = 114325112887 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114325112903.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114325112963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378559826 + ... + 378560127.

It is an arithmetic number, because the mean of its divisors is an integer number (28770558252).

Almost surely, 2114325112903 is an apocalyptic number.

114325112903 is a deficient number, since it is larger than the sum of its proper divisors (757120105).

114325112903 is an equidigital number, since it uses as much as digits as its factorization.

114325112903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 757120104.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 114325112903 in words is "one hundred fourteen billion, three hundred twenty-five million, one hundred twelve thousand, nine hundred three".

Divisors: 1 151 757119953 114325112903