Base | Representation |
---|---|
bin | 10101010010111011… |
… | …11010000100010011 |
3 | 1002111210102212211022 |
4 | 22221131322010103 |
5 | 141403334432430 |
6 | 5130255310055 |
7 | 553215644240 |
oct | 125135720423 |
9 | 32453385738 |
10 | 11433124115 |
11 | 4937778406 |
12 | 2270b1b32b |
13 | 1102895bca |
14 | 7a66185c7 |
15 | 46dae74e5 |
hex | 2a977a113 |
11433124115 has 32 divisors (see below), whose sum is σ = 15912499200. Its totient is φ = 7724242944.
The previous prime is 11433124099. The next prime is 11433124133. The reversal of 11433124115 is 51142133411.
11433124115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11433124115 - 24 = 11433124099 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 709427 + ... + 725363.
It is an arithmetic number, because the mean of its divisors is an integer number (497265600).
Almost surely, 211433124115 is an apocalyptic number.
11433124115 is a deficient number, since it is larger than the sum of its proper divisors (4479375085).
11433124115 is a wasteful number, since it uses less digits than its factorization.
11433124115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16251.
The product of its digits is 1440, while the sum is 26.
Adding to 11433124115 its reverse (51142133411), we get a palindrome (62575257526).
The spelling of 11433124115 in words is "eleven billion, four hundred thirty-three million, one hundred twenty-four thousand, one hundred fifteen".
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