114331351 has 4 divisors (see below), whose sum is σ = 114381072. Its totient is φ = 114281632.

The previous prime is 114331337. The next prime is 114331361. The reversal of 114331351 is 153133411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 153133411 = 4649 ⋅32939.

It is a cyclic number.

It is not a de Polignac number, because 114331351 - 2⁷ = 114331223 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114331331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21235 + ... + 26068.

It is an arithmetic number, because the mean of its divisors is an integer number (28595268).

Almost surely, 2^114331351 is an apocalyptic number.

114331351 is a deficient number, since it is larger than the sum of its proper divisors (49721).

114331351 is an equidigital number, since it uses as much as digits as its factorization.

114331351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49720.

The product of its digits is 540, while the sum is 22.

The square root of 114331351 is about 10692.5839253195. The cubic root of 114331351 is about 485.3500869820.

Adding to 114331351 its reverse (153133411), we get a palindrome (267464762).

The spelling of 114331351 in words is "one hundred fourteen million, three hundred thirty-one thousand, three hundred fifty-one".