11433140103 has 32 divisors (see below), whose sum is σ = 19173975552. Its totient is φ = 5886720000.

The previous prime is 11433140099. The next prime is 11433140129. The reversal of 11433140103 is 30104133411.

It is not a de Polignac number, because 11433140103 - 2² = 11433140099 is a prime.

It is a super-2 number, since 2×11433140103² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a self number, because there is not a number n which added to its sum of digits gives 11433140103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11433141103) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 192898 + ... + 245103.

It is an arithmetic number, because the mean of its divisors is an integer number (599186736).

Almost surely, 2^11433140103 is an apocalyptic number.

11433140103 is a deficient number, since it is larger than the sum of its proper divisors (7740835449).

11433140103 is a wasteful number, since it uses less digits than its factorization.

11433140103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 438135.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11433140103 its reverse (30104133411), we get a palindrome (41537273514).

The spelling of 11433140103 in words is "eleven billion, four hundred thirty-three million, one hundred forty thousand, one hundred three".