Base | Representation |
---|---|
bin | 10101010010111011… |
… | …11110000001101010 |
3 | 1002111210110201001212 |
4 | 22221131332001222 |
5 | 141403340442310 |
6 | 5130255513122 |
7 | 553216042433 |
oct | 125135760152 |
9 | 32453421055 |
10 | 11433140330 |
11 | 4937789607 |
12 | 2270b287a2 |
13 | 11028a03c1 |
14 | 7a662048a |
15 | 46daec205 |
hex | 2a977e06a |
11433140330 has 32 divisors (see below), whose sum is σ = 20927731968. Its totient is φ = 4495982400.
The previous prime is 11433140297. The next prime is 11433140359. The reversal of 11433140330 is 3304133411.
It is a junction number, because it is equal to n+sod(n) for n = 11433140296 and 11433140305.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1662479 + ... + 1669341.
It is an arithmetic number, because the mean of its divisors is an integer number (653991624).
Almost surely, 211433140330 is an apocalyptic number.
11433140330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11433140330 is a deficient number, since it is larger than the sum of its proper divisors (9494591638).
11433140330 is a wasteful number, since it uses less digits than its factorization.
11433140330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9662.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11433140330 its reverse (3304133411), we get a palindrome (14737273741).
The spelling of 11433140330 in words is "eleven billion, four hundred thirty-three million, one hundred forty thousand, three hundred thirty".
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