Base | Representation |
---|---|
bin | 10101010010111011… |
… | …11110101011011011 |
3 | 1002111210110211201212 |
4 | 22221131332223123 |
5 | 141403341034003 |
6 | 5130255533335 |
7 | 553216053302 |
oct | 125135765333 |
9 | 32453424655 |
10 | 11433143003 |
11 | 4937790617 |
12 | 2270b2a24b |
13 | 11028a1699 |
14 | 7a6621439 |
15 | 46daecdd8 |
hex | 2a977eadb |
11433143003 has 4 divisors (see below), whose sum is σ = 11433381960. Its totient is φ = 11432904048.
The previous prime is 11433142969. The next prime is 11433143039. The reversal of 11433143003 is 30034133411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30034133411 = 71693 ⋅418927.
It is a cyclic number.
It is not a de Polignac number, because 11433143003 - 224 = 11416365787 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11433143003.
It is not an unprimeable number, because it can be changed into a prime (11433143203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20225 + ... + 152562.
It is an arithmetic number, because the mean of its divisors is an integer number (2858345490).
Almost surely, 211433143003 is an apocalyptic number.
11433143003 is a deficient number, since it is larger than the sum of its proper divisors (238957).
11433143003 is an equidigital number, since it uses as much as digits as its factorization.
11433143003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238956.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11433143003 its reverse (30034133411), we get a palindrome (41467276414).
The spelling of 11433143003 in words is "eleven billion, four hundred thirty-three million, one hundred forty-three thousand, three".
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