114331500131 has 8 divisors (see below), whose sum is σ = 115357636944. Its totient is φ = 113305615360.

The previous prime is 114331500121. The next prime is 114331500169. The reversal of 114331500131 is 131005133411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114331500131 is a prime.

It is a super-2 number, since 2×114331500131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114331500097 and 114331500106.

It is not an unprimeable number, because it can be changed into a prime (114331500121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 916211 + ... + 1033491.

It is an arithmetic number, because the mean of its divisors is an integer number (14419704618).

Almost surely, 2^114331500131 is an apocalyptic number.

114331500131 is a deficient number, since it is larger than the sum of its proper divisors (1026136813).

114331500131 is a wasteful number, since it uses less digits than its factorization.

114331500131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126021.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 114331500131 its reverse (131005133411), we get a palindrome (245336633542).

The spelling of 114331500131 in words is "one hundred fourteen billion, three hundred thirty-one million, five hundred thousand, one hundred thirty-one".