1143320131 has 2 divisors, whose sum is σ = 1143320132. Its totient is φ = 1143320130.

The previous prime is 1143320119. The next prime is 1143320149. The reversal of 1143320131 is 1310233411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1143320131 - 2²⁷ = 1009102403 is a prime.

It is a super-2 number, since 2×1143320131² = 2614361843899714322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1143320099 and 1143320108.

It is not a weakly prime, because it can be changed into another prime (1143320111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571660065 + 571660066.

It is an arithmetic number, because the mean of its divisors is an integer number (571660066).

Almost surely, 2^1143320131 is an apocalyptic number.

1143320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143320131 is an equidigital number, since it uses as much as digits as its factorization.

1143320131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1143320131 is about 33813.0171827360. The cubic root of 1143320131 is about 1045.6570826846.

Adding to 1143320131 its reverse (1310233411), we get a palindrome (2453553542).

The spelling of 1143320131 in words is "one billion, one hundred forty-three million, three hundred twenty thousand, one hundred thirty-one".