Base | Representation |
---|---|
bin | 11001111111101111111111… |
… | …000110010111011101001001 |
3 | 112222211000220122202000201111 |
4 | 121333233333012113131021 |
5 | 104441203431130424431 |
6 | 1043055222520450321 |
7 | 33040133616562606 |
oct | 3177577706273511 |
9 | 488730818660644 |
10 | 114332014311241 |
11 | 3347aa314a3a21 |
12 | 109a63883199a1 |
13 | 4ba46026a8c0c |
14 | 20339b016d6ad |
15 | d340887437b1 |
hex | 67fbff197749 |
114332014311241 has 64 divisors (see below), whose sum is σ = 125119862784000. Its totient is φ = 104159239430400.
The previous prime is 114332014311233. The next prime is 114332014311247. The reversal of 114332014311241 is 142113410233411.
It is a cyclic number.
It is not a de Polignac number, because 114332014311241 - 23 = 114332014311233 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114332014311247) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5088422355 + ... + 5088444823.
It is an arithmetic number, because the mean of its divisors is an integer number (1954997856000).
Almost surely, 2114332014311241 is an apocalyptic number.
It is an amenable number.
114332014311241 is a deficient number, since it is larger than the sum of its proper divisors (10787848472759).
114332014311241 is a wasteful number, since it uses less digits than its factorization.
114332014311241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23110.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 114332014311241 its reverse (142113410233411), we get a palindrome (256445424544652).
The spelling of 114332014311241 in words is "one hundred fourteen trillion, three hundred thirty-two billion, fourteen million, three hundred eleven thousand, two hundred forty-one".
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