Base | Representation |
---|---|
bin | 10000101000110011111… |
… | …101010001011111111101 |
3 | 11001022010211202022100121 |
4 | 100220303331101133331 |
5 | 122213021222014323 |
6 | 2233123454054541 |
7 | 145413600106024 |
oct | 20506375213775 |
9 | 4038124668317 |
10 | 1143333001213 |
11 | 400980744197 |
12 | 165703aaa451 |
13 | 83a7b525bb0 |
14 | 3d4a25a18bb |
15 | 1eb19da8a5d |
hex | 10a33f517fd |
1143333001213 has 16 divisors (see below), whose sum is σ = 1234355234112. Its totient is φ = 1052752608000.
The previous prime is 1143333001189. The next prime is 1143333001219. The reversal of 1143333001213 is 3121003333411.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1143333001213 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1143333001219) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10046118 + ... + 10159288.
It is an arithmetic number, because the mean of its divisors is an integer number (77147202132).
Almost surely, 21143333001213 is an apocalyptic number.
1143333001213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1143333001213 is a deficient number, since it is larger than the sum of its proper divisors (91022232899).
1143333001213 is a wasteful number, since it uses less digits than its factorization.
1143333001213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115116.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1143333001213 its reverse (3121003333411), we get a palindrome (4264336334624).
The spelling of 1143333001213 in words is "one trillion, one hundred forty-three billion, three hundred thirty-three million, one thousand, two hundred thirteen".
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