Base | Representation |
---|---|
bin | 110101001111011010… |
… | …0001001011110101111 |
3 | 101221010002212200121211 |
4 | 1222132310021132233 |
5 | 3333123401321033 |
6 | 124305114135251 |
7 | 11155202510341 |
oct | 1523664113657 |
9 | 357102780554 |
10 | 114333620143 |
11 | 44541391066 |
12 | 1a1aa121527 |
13 | aa2128b092 |
14 | 576897d291 |
15 | 2e927bd2cd |
hex | 1a9ed097af |
114333620143 has 2 divisors, whose sum is σ = 114333620144. Its totient is φ = 114333620142.
The previous prime is 114333620119. The next prime is 114333620147. The reversal of 114333620143 is 341026333411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114333620143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114333620147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57166810071 + 57166810072.
It is an arithmetic number, because the mean of its divisors is an integer number (57166810072).
Almost surely, 2114333620143 is an apocalyptic number.
114333620143 is a deficient number, since it is larger than the sum of its proper divisors (1).
114333620143 is an equidigital number, since it uses as much as digits as its factorization.
114333620143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 114333620143 its reverse (341026333411), we get a palindrome (455359953554).
The spelling of 114333620143 in words is "one hundred fourteen billion, three hundred thirty-three million, six hundred twenty thousand, one hundred forty-three".
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