11433400232231 has 2 divisors, whose sum is σ = 11433400232232. Its totient is φ = 11433400232230.

The previous prime is 11433400232213. The next prime is 11433400232237. The reversal of 11433400232231 is 13223200433411.

Together with previous prime (11433400232213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11433400232231 - 2²² = 11433396037927 is a prime.

It is a super-2 number, since 2×11433400232231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11433400232194 and 11433400232203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11433400232237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716700116115 + 5716700116116.

It is an arithmetic number, because the mean of its divisors is an integer number (5716700116116).

Almost surely, 2^{11433400232231} is an apocalyptic number.

11433400232231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11433400232231 is an equidigital number, since it uses as much as digits as its factorization.

11433400232231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 11433400232231 its reverse (13223200433411), we get a palindrome (24656600665642).

The spelling of 11433400232231 in words is "eleven trillion, four hundred thirty-three billion, four hundred million, two hundred thirty-two thousand, two hundred thirty-one".