114334841381 has 2 divisors, whose sum is σ = 114334841382. Its totient is φ = 114334841380.

The previous prime is 114334841281. The next prime is 114334841393. The reversal of 114334841381 is 183148433411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108023968900 + 6310872481 = 328670^2 + 79441^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114334841381 is a prime.

It is a super-2 number, since 2×114334841381² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114334841281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57167420690 + 57167420691.

It is an arithmetic number, because the mean of its divisors is an integer number (57167420691).

Almost surely, 2^114334841381 is an apocalyptic number.

It is an amenable number.

114334841381 is a deficient number, since it is larger than the sum of its proper divisors (1).

114334841381 is an equidigital number, since it uses as much as digits as its factorization.

114334841381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 110592, while the sum is 41.

The spelling of 114334841381 in words is "one hundred fourteen billion, three hundred thirty-four million, eight hundred forty-one thousand, three hundred eighty-one".