Base | Representation |
---|---|
bin | 10000101000111000001… |
… | …001110101100010110111 |
3 | 11001022022202020010001202 |
4 | 100220320021311202313 |
5 | 122213142232402242 |
6 | 2233134451043115 |
7 | 145415413366244 |
oct | 20507011654267 |
9 | 4038282203052 |
10 | 1143403403447 |
11 | 400a0745a458 |
12 | 1657235a049b |
13 | 83a8cca5816 |
14 | 3d4aba8a5cb |
15 | 1eb21163932 |
hex | 10a382758b7 |
1143403403447 has 2 divisors, whose sum is σ = 1143403403448. Its totient is φ = 1143403403446.
The previous prime is 1143403403423. The next prime is 1143403403473. The reversal of 1143403403447 is 7443043043411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1143403403447 - 212 = 1143403399351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1143403403447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1143403403407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571701701723 + 571701701724.
It is an arithmetic number, because the mean of its divisors is an integer number (571701701724).
Almost surely, 21143403403447 is an apocalyptic number.
1143403403447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143403403447 is an equidigital number, since it uses as much as digits as its factorization.
1143403403447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 38.
Adding to 1143403403447 its reverse (7443043043411), we get a palindrome (8586446446858).
The spelling of 1143403403447 in words is "one trillion, one hundred forty-three billion, four hundred three million, four hundred three thousand, four hundred forty-seven".
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