Base | Representation |
---|---|
bin | 11001111111111000011101… |
… | …010011111111100000000101 |
3 | 112222211220101122000111212211 |
4 | 121333320131103333200011 |
5 | 104441331043422243323 |
6 | 1043103325321143421 |
7 | 33040605216364435 |
oct | 3177703523774005 |
9 | 488756348014784 |
10 | 114341111134213 |
11 | 3348387a406737 |
12 | 109a80a692ab71 |
13 | 4ba54222298c2 |
14 | 20341d438a2c5 |
15 | d3441c19870d |
hex | 67fe1d4ff805 |
114341111134213 has 2 divisors, whose sum is σ = 114341111134214. Its totient is φ = 114341111134212.
The previous prime is 114341111134189. The next prime is 114341111134249. The reversal of 114341111134213 is 312431111143411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 64495788479329 + 49845322654884 = 8030927^2 + 7060122^2 .
It is a cyclic number.
It is not a de Polignac number, because 114341111134213 - 221 = 114341109037061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114341111134273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57170555567106 + 57170555567107.
It is an arithmetic number, because the mean of its divisors is an integer number (57170555567107).
Almost surely, 2114341111134213 is an apocalyptic number.
It is an amenable number.
114341111134213 is a deficient number, since it is larger than the sum of its proper divisors (1).
114341111134213 is an equidigital number, since it uses as much as digits as its factorization.
114341111134213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3456, while the sum is 31.
Adding to 114341111134213 its reverse (312431111143411), we get a palindrome (426772222277624).
The spelling of 114341111134213 in words is "one hundred fourteen trillion, three hundred forty-one billion, one hundred eleven million, one hundred thirty-four thousand, two hundred thirteen".
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