Base | Representation |
---|---|
bin | 11001111111111010100000… |
… | …011100010110010011110011 |
3 | 112222212010001221201101120201 |
4 | 121333322200130112103303 |
5 | 104441400100122440313 |
6 | 1043104331511020031 |
7 | 33041013562206634 |
oct | 3177724034262363 |
9 | 488763057641521 |
10 | 114343311140083 |
11 | 334847a923a703 |
12 | 109a85bb66a617 |
13 | 4ba56b2c60b1c |
14 | 203436262988b |
15 | d344ea3b70dd |
hex | 67fea07164f3 |
114343311140083 has 2 divisors, whose sum is σ = 114343311140084. Its totient is φ = 114343311140082.
The previous prime is 114343311140081. The next prime is 114343311140101. The reversal of 114343311140083 is 380041113343411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114343311140083 - 21 = 114343311140081 is a prime.
Together with 114343311140081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (114343311140081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57171655570041 + 57171655570042.
It is an arithmetic number, because the mean of its divisors is an integer number (57171655570042).
Almost surely, 2114343311140083 is an apocalyptic number.
114343311140083 is a deficient number, since it is larger than the sum of its proper divisors (1).
114343311140083 is an equidigital number, since it uses as much as digits as its factorization.
114343311140083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 37.
Adding to 114343311140083 its reverse (380041113343411), we get a palindrome (494384424483494).
The spelling of 114343311140083 in words is "one hundred fourteen trillion, three hundred forty-three billion, three hundred eleven million, one hundred forty thousand, eighty-three".
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