Base | Representation |
---|---|
bin | 11001111111111010100000… |
… | …011100010110010110111111 |
3 | 112222212010001221201101212021 |
4 | 121333322200130112112333 |
5 | 104441400100122442122 |
6 | 1043104331511021011 |
7 | 33041013562210345 |
oct | 3177724034262677 |
9 | 488763057641767 |
10 | 114343311140287 |
11 | 334847a923a879 |
12 | 109a85bb66a767 |
13 | 4ba56b2c60c48 |
14 | 2034362629995 |
15 | d344ea3b71c7 |
hex | 67fea07165bf |
114343311140287 has 2 divisors, whose sum is σ = 114343311140288. Its totient is φ = 114343311140286.
The previous prime is 114343311140101. The next prime is 114343311140299. The reversal of 114343311140287 is 782041113343411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114343311140287 - 211 = 114343311138239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114343311144287) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57171655570143 + 57171655570144.
It is an arithmetic number, because the mean of its divisors is an integer number (57171655570144).
Almost surely, 2114343311140287 is an apocalyptic number.
114343311140287 is a deficient number, since it is larger than the sum of its proper divisors (1).
114343311140287 is an equidigital number, since it uses as much as digits as its factorization.
114343311140287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 43.
Adding to 114343311140287 its reverse (782041113343411), we get a palindrome (896384424483698).
The spelling of 114343311140287 in words is "one hundred fourteen trillion, three hundred forty-three billion, three hundred eleven million, one hundred forty thousand, two hundred eighty-seven".
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