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11434431153 = 33811477051
BaseRepresentation
bin10101010011000101…
…11001001010110001
31002111212220021202010
422221202321022301
5141404203244103
65130343313133
7553233026655
oct125142711261
932455807663
1011434431153
114938490402
12227144b7a9
131102c32ac2
147a6878a65
1546dca4903
hex2a98b92b1

11434431153 has 4 divisors (see below), whose sum is σ = 15245908208. Its totient is φ = 7622954100.

The previous prime is 11434431133. The next prime is 11434431181. The reversal of 11434431153 is 35113443411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11434431153 - 28 = 11434430897 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11434431153.

It is not an unprimeable number, because it can be changed into a prime (11434431133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905738523 + ... + 1905738528.

It is an arithmetic number, because the mean of its divisors is an integer number (3811477052).

Almost surely, 211434431153 is an apocalyptic number.

It is an amenable number.

11434431153 is a deficient number, since it is larger than the sum of its proper divisors (3811477055).

11434431153 is an equidigital number, since it uses as much as digits as its factorization.

11434431153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3811477054.

The product of its digits is 8640, while the sum is 30.

Adding to 11434431153 its reverse (35113443411), we get a palindrome (46547874564).

The spelling of 11434431153 in words is "eleven billion, four hundred thirty-four million, four hundred thirty-one thousand, one hundred fifty-three".

Divisors: 1 3 3811477051 11434431153