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1143550045551 = 3478110284011
BaseRepresentation
bin10000101001000000111…
…001001110110101101111
311001022200222011022012210
4100221000321032311233
5122213442302424201
62233201210101503
7145422144002244
oct20510071166557
94038628138183
101143550045551
11400a82208881
1216576471a893
1383ab449a1b4
143d4c333d5cb
151eb2de7d1d6
hex10a40e4ed6f

1143550045551 has 8 divisors (see below), whose sum is σ = 1557174530304. Its totient is φ = 746146128920.

The previous prime is 1143550045523. The next prime is 1143550045571. The reversal of 1143550045551 is 1555400553411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1143550045551 - 213 = 1143550037359 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1143550045501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4055141865 + ... + 4055142146.

It is an arithmetic number, because the mean of its divisors is an integer number (194646816288).

Almost surely, 21143550045551 is an apocalyptic number.

1143550045551 is a deficient number, since it is larger than the sum of its proper divisors (413624484753).

1143550045551 is an equidigital number, since it uses as much as digits as its factorization.

1143550045551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8110284061.

The product of its (nonzero) digits is 150000, while the sum is 39.

Adding to 1143550045551 its reverse (1555400553411), we get a palindrome (2698950598962).

The spelling of 1143550045551 in words is "one trillion, one hundred forty-three billion, five hundred fifty million, forty-five thousand, five hundred fifty-one".

Divisors: 1 3 47 141 8110284011 24330852033 381183348517 1143550045551