Base | Representation |
---|---|
bin | 10000101001011100011… |
… | …101000001100001101011 |
3 | 11001100220012012000011102 |
4 | 100221130131001201223 |
5 | 122220414134204120 |
6 | 2233315124152015 |
7 | 145436460031352 |
oct | 20513435014153 |
9 | 4040805160142 |
10 | 1144012413035 |
11 | 40119a201368 |
12 | 16587353860b |
13 | 83b5920721b |
14 | 3d5288da999 |
15 | 1eb59860d75 |
hex | 10a5c74186b |
1144012413035 has 4 divisors (see below), whose sum is σ = 1372814895648. Its totient is φ = 915209930424.
The previous prime is 1144012413007. The next prime is 1144012413043. The reversal of 1144012413035 is 5303142104411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1144012413035 - 26 = 1144012412971 is a prime.
It is a super-2 number, since 2×11440124130352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1144012412989 and 1144012413007.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114401241299 + ... + 114401241308.
It is an arithmetic number, because the mean of its divisors is an integer number (343203723912).
Almost surely, 21144012413035 is an apocalyptic number.
1144012413035 is a deficient number, since it is larger than the sum of its proper divisors (228802482613).
1144012413035 is an equidigital number, since it uses as much as digits as its factorization.
1144012413035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228802482612.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1144012413035 its reverse (5303142104411), we get a palindrome (6447154517446).
The spelling of 1144012413035 in words is "one trillion, one hundred forty-four billion, twelve million, four hundred thirteen thousand, thirty-five".
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