1144043211433 has 2 divisors, whose sum is σ = 1144043211434. Its totient is φ = 1144043211432.

The previous prime is 1144043211293. The next prime is 1144043211461. The reversal of 1144043211433 is 3341123404411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 763591102569 + 380452108864 = 873837^2 + 616808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1144043211433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1144043211395 and 1144043211404.

It is not a weakly prime, because it can be changed into another prime (1144043215433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572021605716 + 572021605717.

It is an arithmetic number, because the mean of its divisors is an integer number (572021605717).

Almost surely, 2^{1144043211433} is an apocalyptic number.

It is an amenable number.

1144043211433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1144043211433 is an equidigital number, since it uses as much as digits as its factorization.

1144043211433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1144043211433 its reverse (3341123404411), we get a palindrome (4485166615844).

The spelling of 1144043211433 in words is "one trillion, one hundred forty-four billion, forty-three million, two hundred eleven thousand, four hundred thirty-three".