114410243313001 has 4 divisors (see below), whose sum is σ = 114498048566272. Its totient is φ = 114322438059732.

The previous prime is 114410243312957. The next prime is 114410243313019. The reversal of 114410243313001 is 100313342014411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114410243313001 - 2¹⁷ = 114410243181929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114410243313101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43902624681 + ... + 43902627286.

It is an arithmetic number, because the mean of its divisors is an integer number (28624512141568).

Almost surely, 2^{114410243313001} is an apocalyptic number.

It is an amenable number.

114410243313001 is a deficient number, since it is larger than the sum of its proper divisors (87805253271).

114410243313001 is an equidigital number, since it uses as much as digits as its factorization.

114410243313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87805253270.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 114410243313001 its reverse (100313342014411), we get a palindrome (214723585327412).

The spelling of 114410243313001 in words is "one hundred fourteen trillion, four hundred ten billion, two hundred forty-three million, three hundred thirteen thousand, one".