Base | Representation |
---|---|
bin | 110101010001101101… |
… | …1011110111010110001 |
3 | 101221022111120001021222 |
4 | 1222203123132322301 |
5 | 3333303211243213 |
6 | 124320521354425 |
7 | 11160132540434 |
oct | 1524333367261 |
9 | 357274501258 |
10 | 114411040433 |
11 | 44581060078 |
12 | 1a210038a15 |
13 | aa343271c1 |
14 | 5774d7381b |
15 | 2e994b2808 |
hex | 1aa36deeb1 |
114411040433 has 4 divisors (see below), whose sum is σ = 120432674160. Its totient is φ = 108389406708.
The previous prime is 114411040399. The next prime is 114411040477. The reversal of 114411040433 is 334040114411.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114411040433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114419040433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3010816835 + ... + 3010816872.
It is an arithmetic number, because the mean of its divisors is an integer number (30108168540).
Almost surely, 2114411040433 is an apocalyptic number.
It is an amenable number.
114411040433 is a deficient number, since it is larger than the sum of its proper divisors (6021633727).
114411040433 is an equidigital number, since it uses as much as digits as its factorization.
114411040433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6021633726.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 114411040433 its reverse (334040114411), we get a palindrome (448451154844).
The spelling of 114411040433 in words is "one hundred fourteen billion, four hundred eleven million, forty thousand, four hundred thirty-three".
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