11441443113001 has 4 divisors (see below), whose sum is σ = 12481574305104. Its totient is φ = 10401311920900.

The previous prime is 11441443112933. The next prime is 11441443113053. The reversal of 11441443113001 is 10031134414411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11441443113001 - 2¹⁹ = 11441442588713 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11441443113601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520065596035 + ... + 520065596056.

It is an arithmetic number, because the mean of its divisors is an integer number (3120393576276).

Almost surely, 2^{11441443113001} is an apocalyptic number.

11441443113001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11441443113001 is a deficient number, since it is larger than the sum of its proper divisors (1040131192103).

11441443113001 is a wasteful number, since it uses less digits than its factorization.

11441443113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1040131192102.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 11441443113001 its reverse (10031134414411), we get a palindrome (21472577527412).

The spelling of 11441443113001 in words is "eleven trillion, four hundred forty-one billion, four hundred forty-three million, one hundred thirteen thousand, one".