Base | Representation |
---|---|
bin | 110101010010000000… |
… | …1111010010110111111 |
3 | 101221100012111212001021 |
4 | 1222210001322112333 |
5 | 3333313301124203 |
6 | 124321521325011 |
7 | 11160314265346 |
oct | 1524401722677 |
9 | 357305455037 |
10 | 114421114303 |
11 | 44586810791 |
12 | 1a213496767 |
13 | aa36443582 |
14 | 5776436b5d |
15 | 2e9a3025bd |
hex | 1aa407a5bf |
114421114303 has 4 divisors (see below), whose sum is σ = 114433370368. Its totient is φ = 114408858240.
The previous prime is 114421114261. The next prime is 114421114319. The reversal of 114421114303 is 303411124411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303411124411 = 233 ⋅1302193667.
It is a cyclic number.
It is not a de Polignac number, because 114421114303 - 221 = 114419017151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114421114333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6114018 + ... + 6132703.
It is an arithmetic number, because the mean of its divisors is an integer number (28608342592).
Almost surely, 2114421114303 is an apocalyptic number.
114421114303 is a deficient number, since it is larger than the sum of its proper divisors (12256065).
114421114303 is an equidigital number, since it uses as much as digits as its factorization.
114421114303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12256064.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 114421114303 its reverse (303411124411), we get a palindrome (417832238714).
The spelling of 114421114303 in words is "one hundred fourteen billion, four hundred twenty-one million, one hundred fourteen thousand, three hundred three".
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