Base | Representation |
---|---|
bin | 10000101001101110001… |
… | …101011000111001110101 |
3 | 11001101122221201110020221 |
4 | 100221232031120321311 |
5 | 122222021414214443 |
6 | 2233404445054341 |
7 | 145450035046255 |
oct | 20515615307165 |
9 | 4041587643227 |
10 | 1144310304373 |
11 | 401332375555 |
12 | 1659372573b1 |
13 | 83ba5b472a2 |
14 | 3d5562c1965 |
15 | 1eb75aa4eed |
hex | 10a6e358e75 |
1144310304373 has 2 divisors, whose sum is σ = 1144310304374. Its totient is φ = 1144310304372.
The previous prime is 1144310304341. The next prime is 1144310304461. The reversal of 1144310304373 is 3734030134411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 583454600964 + 560855703409 = 763842^2 + 748903^2 .
It is a cyclic number.
It is not a de Polignac number, because 1144310304373 - 25 = 1144310304341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1144310304323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572155152186 + 572155152187.
It is an arithmetic number, because the mean of its divisors is an integer number (572155152187).
Almost surely, 21144310304373 is an apocalyptic number.
It is an amenable number.
1144310304373 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144310304373 is an equidigital number, since it uses as much as digits as its factorization.
1144310304373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 34.
Adding to 1144310304373 its reverse (3734030134411), we get a palindrome (4878340438784).
The spelling of 1144310304373 in words is "one trillion, one hundred forty-four billion, three hundred ten million, three hundred four thousand, three hundred seventy-three".
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