Base | Representation |
---|---|
bin | 10101010100001000… |
… | …00000010010001011 |
3 | 1002112111020021022211 |
4 | 22222010000102023 |
5 | 141413414023201 |
6 | 5131253325551 |
7 | 553366560541 |
oct | 125204002213 |
9 | 32474207284 |
10 | 11443111051 |
11 | 4942379779 |
12 | 22743368b7 |
13 | 1104981838 |
14 | 7a7a97d91 |
15 | 46e91b651 |
hex | 2aa10048b |
11443111051 has 2 divisors, whose sum is σ = 11443111052. Its totient is φ = 11443111050.
The previous prime is 11443111039. The next prime is 11443111061. The reversal of 11443111051 is 15011134411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11443111051 - 27 = 11443110923 is a prime.
It is not a weakly prime, because it can be changed into another prime (11443111061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5721555525 + 5721555526.
It is an arithmetic number, because the mean of its divisors is an integer number (5721555526).
Almost surely, 211443111051 is an apocalyptic number.
11443111051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11443111051 is an equidigital number, since it uses as much as digits as its factorization.
11443111051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 11443111051 its reverse (15011134411), we get a palindrome (26454245462).
The spelling of 11443111051 in words is "eleven billion, four hundred forty-three million, one hundred eleven thousand, fifty-one".
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