Base | Representation |
---|---|
bin | 10000101001101110110… |
… | …111011101011110110011 |
3 | 11001101200201110202220221 |
4 | 100221232313131132303 |
5 | 122222032230130141 |
6 | 2233405521313511 |
7 | 145450230562222 |
oct | 20515667353663 |
9 | 4041621422827 |
10 | 1144321333171 |
11 | 401338618665 |
12 | 16593aa95897 |
13 | 83ba82091c3 |
14 | 3d557952cb9 |
15 | 1eb76a32bd1 |
hex | 10a6eddd7b3 |
1144321333171 has 2 divisors, whose sum is σ = 1144321333172. Its totient is φ = 1144321333170.
The previous prime is 1144321333091. The next prime is 1144321333213. The reversal of 1144321333171 is 1713331234411.
It is a strong prime.
It is an emirp because it is prime and its reverse (1713331234411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1144321333171 - 211 = 1144321331123 is a prime.
It is not a weakly prime, because it can be changed into another prime (1144321330171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572160666585 + 572160666586.
It is an arithmetic number, because the mean of its divisors is an integer number (572160666586).
Almost surely, 21144321333171 is an apocalyptic number.
1144321333171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144321333171 is an equidigital number, since it uses as much as digits as its factorization.
1144321333171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18144, while the sum is 34.
Adding to 1144321333171 its reverse (1713331234411), we get a palindrome (2857652567582).
The spelling of 1144321333171 in words is "one trillion, one hundred forty-four billion, three hundred twenty-one million, three hundred thirty-three thousand, one hundred seventy-one".
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