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1144321333213 is a prime number
BaseRepresentation
bin10000101001101110110…
…111011101011111011101
311001101200201110202222111
4100221232313131133131
5122222032230130323
62233405521314021
7145450230562312
oct20515667353735
94041621422874
101144321333213
114013386186a3
1216593aa95911
1383ba8209226
143d557952d09
151eb76a32c0d
hex10a6eddd7dd

1144321333213 has 2 divisors, whose sum is σ = 1144321333214. Its totient is φ = 1144321333212.

The previous prime is 1144321333171. The next prime is 1144321333231. The reversal of 1144321333213 is 3123331234411.

Together with next prime (1144321333231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1140169077369 + 4152255844 = 1067787^2 + 64438^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1144321333213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1144321333513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572160666606 + 572160666607.

It is an arithmetic number, because the mean of its divisors is an integer number (572160666607).

Almost surely, 21144321333213 is an apocalyptic number.

It is an amenable number.

1144321333213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1144321333213 is an equidigital number, since it uses as much as digits as its factorization.

1144321333213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15552, while the sum is 31.

Adding to 1144321333213 its reverse (3123331234411), we get a palindrome (4267652567624).

The spelling of 1144321333213 in words is "one trillion, one hundred forty-four billion, three hundred twenty-one million, three hundred thirty-three thousand, two hundred thirteen".