1144330000037 has 4 divisors (see below), whose sum is σ = 1307805714336. Its totient is φ = 980854285740.

The previous prime is 1144330000031. The next prime is 1144330000061. The reversal of 1144330000037 is 7300000334411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1144330000037 - 2⁸ = 1144329999781 is a prime.

It is a super-2 number, since 2×1144330000037² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1144329999970 and 1144330000015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1144330000031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81737857139 + ... + 81737857152.

It is an arithmetic number, because the mean of its divisors is an integer number (326951428584).

Almost surely, 2^{1144330000037} is an apocalyptic number.

It is an amenable number.

1144330000037 is a deficient number, since it is larger than the sum of its proper divisors (163475714299).

1144330000037 is an equidigital number, since it uses as much as digits as its factorization.

1144330000037 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163475714298.

The product of its (nonzero) digits is 3024, while the sum is 26.

Adding to 1144330000037 its reverse (7300000334411), we get a palindrome (8444330334448).

The spelling of 1144330000037 in words is "one trillion, one hundred forty-four billion, three hundred thirty million, thirty-seven", and thus it is an aban number.