114433141314001 has 2 divisors, whose sum is σ = 114433141314002. Its totient is φ = 114433141314000.

The previous prime is 114433141313993. The next prime is 114433141314029. The reversal of 114433141314001 is 100413141334411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94885035401025 + 19548105912976 = 9740895^2 + 4421324^2 .

It is a cyclic number.

It is not a de Polignac number, because 114433141314001 - 2³ = 114433141313993 is a prime.

It is not a weakly prime, because it can be changed into another prime (114433141314061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57216570657000 + 57216570657001.

It is an arithmetic number, because the mean of its divisors is an integer number (57216570657001).

Almost surely, 2^{114433141314001} is an apocalyptic number.

It is an amenable number.

114433141314001 is a deficient number, since it is larger than the sum of its proper divisors (1).

114433141314001 is an equidigital number, since it uses as much as digits as its factorization.

114433141314001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 114433141314001 its reverse (100413141334411), we get a palindrome (214846282648412).

The spelling of 114433141314001 in words is "one hundred fourteen trillion, four hundred thirty-three billion, one hundred forty-one million, three hundred fourteen thousand, one".