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1144331429977 is a prime number
BaseRepresentation
bin10000101001101111011…
…101111110100001011001
311001101201102110202010201
4100221233131332201121
5122222042321224402
62233410521542201
7145450412444041
oct20515735764131
94041642422121
101144331429977
1140134329452a
12165942344961
1383baa332b48
143d559020721
151eb77879687
hex10a6f77e859

1144331429977 has 2 divisors, whose sum is σ = 1144331429978. Its totient is φ = 1144331429976.

The previous prime is 1144331429971. The next prime is 1144331430037. The reversal of 1144331429977 is 7799241334411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 576269247376 + 568062182601 = 759124^2 + 753699^2 .

It is a cyclic number.

It is not a de Polignac number, because 1144331429977 - 219 = 1144330905689 is a prime.

It is not a weakly prime, because it can be changed into another prime (1144331429971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572165714988 + 572165714989.

It is an arithmetic number, because the mean of its divisors is an integer number (572165714989).

Almost surely, 21144331429977 is an apocalyptic number.

It is an amenable number.

1144331429977 is a deficient number, since it is larger than the sum of its proper divisors (1).

1144331429977 is an equidigital number, since it uses as much as digits as its factorization.

1144331429977 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4572288, while the sum is 55.

The spelling of 1144331429977 in words is "one trillion, one hundred forty-four billion, three hundred thirty-one million, four hundred twenty-nine thousand, nine hundred seventy-seven".