Base | Representation |
---|---|
bin | 11010000001010100101111… |
… | …101101010010000000010101 |
3 | 120000012101011120201201201021 |
4 | 122001110233231102000111 |
5 | 104444442014211020201 |
6 | 1043221034241201141 |
7 | 33051013640015533 |
oct | 3201245755220025 |
9 | 500171146651637 |
10 | 114440204001301 |
11 | 335118aa788412 |
12 | 10a033409301b1 |
13 | 4bb1884b160b9 |
14 | 2038d14b55153 |
15 | d36cbb947ea1 |
hex | 68152fb52015 |
114440204001301 has 2 divisors, whose sum is σ = 114440204001302. Its totient is φ = 114440204001300.
The previous prime is 114440204001257. The next prime is 114440204001329. The reversal of 114440204001301 is 103100402044411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108914813123076 + 5525390878225 = 10436226^2 + 2350615^2 .
It is a cyclic number.
It is not a de Polignac number, because 114440204001301 - 27 = 114440204001173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114440204031301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57220102000650 + 57220102000651.
It is an arithmetic number, because the mean of its divisors is an integer number (57220102000651).
Almost surely, 2114440204001301 is an apocalyptic number.
It is an amenable number.
114440204001301 is a deficient number, since it is larger than the sum of its proper divisors (1).
114440204001301 is an equidigital number, since it uses as much as digits as its factorization.
114440204001301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 114440204001301 its reverse (103100402044411), we get a palindrome (217540606045712).
The spelling of 114440204001301 in words is "one hundred fourteen trillion, four hundred forty billion, two hundred four million, one thousand, three hundred one".
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