Base | Representation |
---|---|
bin | 110101010010101101… |
… | …0101111010110110011 |
3 | 101221101211022220002101 |
4 | 1222211122233112303 |
5 | 3333340231300201 |
6 | 124324112401231 |
7 | 11161016231002 |
oct | 1524532572663 |
9 | 357354286071 |
10 | 114444400051 |
11 | 44598975703 |
12 | 1a21b246217 |
13 | aa3b207417 |
14 | 5779578c39 |
15 | 2e9c3a1d01 |
hex | 1aa56af5b3 |
114444400051 has 2 divisors, whose sum is σ = 114444400052. Its totient is φ = 114444400050.
The previous prime is 114444400003. The next prime is 114444400087. The reversal of 114444400051 is 150004444411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114444400051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114444399992 and 114444400019.
It is not a weakly prime, because it can be changed into another prime (114444400151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57222200025 + 57222200026.
It is an arithmetic number, because the mean of its divisors is an integer number (57222200026).
Almost surely, 2114444400051 is an apocalyptic number.
114444400051 is a deficient number, since it is larger than the sum of its proper divisors (1).
114444400051 is an equidigital number, since it uses as much as digits as its factorization.
114444400051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5120, while the sum is 28.
Adding to 114444400051 its reverse (150004444411), we get a palindrome (264448844462).
The spelling of 114444400051 in words is "one hundred fourteen billion, four hundred forty-four million, four hundred thousand, fifty-one".
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