Base | Representation |
---|---|
bin | 110101010010101101… |
… | …0101111010110000011 |
3 | 101221101211022220000121 |
4 | 1222211122233112003 |
5 | 3333340231300003 |
6 | 124324112401111 |
7 | 11161016230603 |
oct | 1524532572603 |
9 | 357354286017 |
10 | 114444400003 |
11 | 4459897566a |
12 | 1a21b246197 |
13 | aa3b2073ab |
14 | 5779578c03 |
15 | 2e9c3a1cbd |
hex | 1aa56af583 |
114444400003 has 2 divisors, whose sum is σ = 114444400004. Its totient is φ = 114444400002.
The previous prime is 114444399983. The next prime is 114444400051. The reversal of 114444400003 is 300004444411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114444400003 - 29 = 114444399491 is a prime.
It is not a weakly prime, because it can be changed into another prime (114444406003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57222200001 + 57222200002.
It is an arithmetic number, because the mean of its divisors is an integer number (57222200002).
Almost surely, 2114444400003 is an apocalyptic number.
114444400003 is a deficient number, since it is larger than the sum of its proper divisors (1).
114444400003 is an equidigital number, since it uses as much as digits as its factorization.
114444400003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 114444400003 its reverse (300004444411), we get a palindrome (414448844414).
The spelling of 114444400003 in words is "one hundred fourteen billion, four hundred forty-four million, four hundred thousand, three".
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