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114450033001453 is a prime number
BaseRepresentation
bin11010000001011101111001…
…100011111100001111101101
3120000020022112120201200010221
4122001131321203330033231
5110000122131422021303
61043225341434531341
733051512340105622
oct3201357143741755
9500208476650127
10114450033001453
1133515a93a17736
1210a05224596b51
134bb2790261116
1420395a82c4349
15d371947c94bd
hex6817798fc3ed

114450033001453 has 2 divisors, whose sum is σ = 114450033001454. Its totient is φ = 114450033001452.

The previous prime is 114450033001433. The next prime is 114450033001481. The reversal of 114450033001453 is 354100330054411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90848100656329 + 23601932345124 = 9531427^2 + 4858182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114450033001453 is a prime.

It is a super-2 number, since 2×1144500330014532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114450033001433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57225016500726 + 57225016500727.

It is an arithmetic number, because the mean of its divisors is an integer number (57225016500727).

Almost surely, 2114450033001453 is an apocalyptic number.

It is an amenable number.

114450033001453 is a deficient number, since it is larger than the sum of its proper divisors (1).

114450033001453 is an equidigital number, since it uses as much as digits as its factorization.

114450033001453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 114450033001453 its reverse (354100330054411), we get a palindrome (468550363055864).

The spelling of 114450033001453 in words is "one hundred fourteen trillion, four hundred fifty billion, thirty-three million, one thousand, four hundred fifty-three".