Base | Representation |
---|---|
bin | 10101010100011001… |
… | …10001110111100111 |
3 | 1002112122120010200100 |
4 | 22222030301313213 |
5 | 141420011130203 |
6 | 5131414515143 |
7 | 553425251034 |
oct | 125214616747 |
9 | 32478503610 |
10 | 11445411303 |
11 | 49436aaa07 |
12 | 2275065ab3 |
13 | 11052a8831 |
14 | 7a80d638b |
15 | 46ec22ea3 |
hex | 2aa331de7 |
11445411303 has 12 divisors (see below), whose sum is σ = 16718017680. Its totient is φ = 7544540256.
The previous prime is 11445411301. The next prime is 11445411319. The reversal of 11445411303 is 30311454411.
11445411303 is a `hidden beast` number, since 114 + 4 + 541 + 1 + 3 + 0 + 3 = 666.
It is not a de Polignac number, because 11445411303 - 21 = 11445411301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11445411301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7143651 + ... + 7145252.
It is an arithmetic number, because the mean of its divisors is an integer number (1393168140).
Almost surely, 211445411303 is an apocalyptic number.
11445411303 is a deficient number, since it is larger than the sum of its proper divisors (5272606377).
11445411303 is a wasteful number, since it uses less digits than its factorization.
11445411303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14288998 (or 14288995 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 11445411303 its reverse (30311454411), we get a palindrome (41756865714).
The spelling of 11445411303 in words is "eleven billion, four hundred forty-five million, four hundred eleven thousand, three hundred three".
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